Rectangle a has a length of 2x + 6 and a width of 3x. rectangle b has a length of x + 2 and an area of 12 square units greater than rectangle a’s area. what is a simplified expression for the width of rectangle b?

x + 2
x + 1
6x + 6
6(x + 2)(x + 1)

So here is how you solve for the answer.
Firstly, you solve for the Area of Rectangle A.
The formula for Area is Length x width.
So A = (2x + 6)(3x) and the result is: 6x^2 + 18x
Now, let y be the width of rectangle B.
(x+2) (y) = 6x^2 + 18x + 12
(x+2) y = 6(x+1)(x+2)
y = 6(x+1)
So the final answer would be width is 6x + 6. The answer is the third option. Hope this answer helps.

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