Complete the chart to find the mean, variance and standard deviation. Remember to use commas and round numbers to the nearest tenth.
Х
X-X
IX-X)²
1. 45
= -357.5
The mean is
2. 340
=-62.5
The median is
3. 400
= -2.5
The variance is
4. 825
= 422.5 =
The standard deviation is
ΣΧ=
(X-X)2 = 310,225.2 n=

Anull hypothesis states that the difference between 8 hours of sleep and 3 hours of sleep has no effect on the number of pictures a student will remember during a picture memory interface test (pmit). examining the mit database, an extremely small t-value of 0.1611 is found. this t-value is much smaller than the smallest t-value on the chart for p-value reference. from this information we can: select one: a. accept the null hypothesis because the p-value obtained shows that the difference between the two groups being tested is not statistically significant b. accept the null hypothesis because the p-value obtained was statistically significant c. reject the null hypothesis because of the p-value obtained d. reject the null hypothesis because the data obtained is statistically significant