A system of equations is shown below. Equation 1: 21 - y=-8
Equation 2: 2 + 2y = 6
To begin solving the system of equations, Equation 1 is multiplied by a value of 2 to create Equation 3.
Equation 3: 42 – 2y = -16
Equation 2: 2 + 2y = 6
Which procedure could best be used to eliminate one of the variables?
add Equation 2 to Equation 3
subtract Equation 2 from Equation 3
subtract Equation 3 from Equation 2
multiply Equation 2 by a value of 4

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

-2/

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.