The surface area of the square pyramid shown is 84 square inches. What is the value of $x$ ? Square pyramid with base edge of 6 inches, and a slant height labeled x inches, on a triangular face.

4 inches

Step-by-step explanation:

The surface area, A of a right square pyramid is given by :

A = a² + 2as

Where, s = height of each triangular surface = x

a = base edge of pyramid

Substituting values into the equation :

A = 84 in² ; a = 6 in ; Slant height, s = x

84 = 6² + 2(6 * x)

84 = 36 + 2(6x)

84 = 36 + 12x

84 - 36 = 12x

48 = 12x

48/12 = 12x / 12

4 = x

Hence, Slant height, x = 4 inches

4 inches

Step-by-step explanation:

The surface area, A of a right square pyramid is given by :

A = a² + 2as

Where, s = height of each triangular surface = x

a = base edge of pyramid

Substituting values into the equation :

A = 84 in² ; a = 6 in ; Slant height, s = x

84 = 6² + 2(6 * x)

84 = 36 + 2(6x)

84 = 36 + 12x

84 - 36 = 12x

48 = 12x

48/12 = 12x / 12

4 = x

Hence, Slant height, x = 4 inches

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

never fear papaguy is here

answer