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Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) β sinh2(x) = 1 and (b) 1 β tanh 2(x) = sech 2(x). solution (a) cosh2(x) β sinh2(x) = ex + eβx 2 2 β 2 = e2x + 2 + eβ2x 4 β = 4 = . (b) we start with the identity proved in part (a): cosh2(x) β sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 β sinh2(x) cosh2(x) = 1 or 1 β tanh 2(x) = .
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Mathematics, 22.06.2019 00:20, cjasmine626
What is the slope of the line passing through the points (3,β3) and (5,β7) ? 1. 2 2. 1/2 3. β2 4. β1/2
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(1+cot^2)(1/cot^2-1)/1+tan^2=1β...
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