Factor completely: 2x2 − 18

prime

2(x2 − 9)

2(x + 3)(x − 3)

2(x + 3)(x + 3)

To factor the given function, find a term that is divisible by both terms. For this problem, the factor would be 2, since 2x^2 and -18 are both divisible by 2.

2(x^2 - 9)

You could further factor out x^2 - 9 because it is factorable by (x - 3) and (x + 3). Thus, it would be

2(x -3)(x+3)

10feet apart then both

Neither is the answer