An Oil Rig is 30 meters tall. Mr. Clanton is standing 12 meters from the base of the Rig. At what angle of elevation does he need to look to see the eagle on top of the Rig ? What is the distance from Mr. Clanton to the Eagle ?

Angle of elevation: 68.2°, distance from Mr. clanton to the eagle: 32.3m.

Step-by-step explanation:

I can't draw the diagram , but will try to explain:

the diagram is a right angled triangle, with the opposite as the rig, the adjacent as the distance between mr. clinton and the base of the rig, and the hypotenuse as x.

∅ is the angle of elevation from clinton to the eagle.

Using SOH CAH TOA,

Tan∅ =30÷12

tan∅ =2.5.

∅ =tan^-1( tan raised to power -1 )

∅ =tan^-1(2.5)

∅ = 68.19859051≅68.2 to 3s.f.

To get the distance between mr. clinton and the eagle:

Using SOH CAH TOA;

Cos68.2 =12/x   cross multiplying

x*cos68.2 =12

∴ x = 12 ÷ cos 68.2

= 12 ÷ 0.3713678356

= 32.31297611≅32.3 to 3s.f.

Hope this helps

where is the image?

step-by-step explanation:

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d