Afantasy board game makes use of four dice. the first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. if all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

The total possible outcomes that exist are:

                             2400

We are given four dices:

first is a standard 6-faced die.

The second die has 4 faces.

Third dice has 10 faces.

Fourth dice has 10 faces.

Now when all the dice are thrown together then the total number of possible outcomes are:

( Since there are 4 numbers possible for the first die, 6 for second and 10 each for third and fourth)

                    The answer is:

                           2400

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5