Solve each equation.
2(β3)=14
-5(β1)=40
12(+10)=24
16(+6)=11
57(...
Mathematics, 14.04.2021 01:00, alexiagreen1212
Solve each equation.
2(β3)=14
-5(β1)=40
12(+10)=24
16(+6)=11
57(β9)=25
Answers: 3
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