Mathematics
Mathematics, 13.04.2021 19:30, bige556

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Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) βˆ’ sinh2(x) = 1 and (b) 1 βˆ’ tanh 2(x) = sech 2(x). solution (a) cosh2(x) βˆ’ sinh2(x) = ex + eβˆ’x 2 2 βˆ’ 2 = e2x + 2 + eβˆ’2x 4 βˆ’ = 4 = . (b) we start with the identity proved in part (a): cosh2(x) βˆ’ sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 βˆ’ sinh2(x) cosh2(x) = 1 or 1 βˆ’ tanh 2(x) = .
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