An object is launched at an upward velocity of 96 feet per second from the top of a building 160 feet above the ground. Use the vertical motion model h= - 16t2 + vt + c where h is the ending height of the object, c is the initial height, in feet, of the object, t is the time in seconds, and vis the velocity of the object. How long will it take the object to reach the maximum height and what is the maximum height? Fill in the blanks with the appropriate values. At seconds, the object's maximum height will be feet.​

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24

the answer is:

the correct option is the option b.

to calculate the surface area of the right cylinder, we need to use the following formula:

from the picture we know that:

so, substituting and calculting we have:

hence, we have that the correct option is the option b.

have a nice day!