Know how to calculate point est., confidence interval, max tolerable error. Know the effect when you change the confidence level and the sample size. A high school surveyed their graduates on their starting salaries. 300 were returned. The average starting salary of the surveys returned was $32,000 with a standard deviation of $5,000. 1. What is the point estimate for the starting salary of the graduates?
2. What is the 95% confidence interval for the average salary of all graduates?
3. What is the value of the Maximum Tolerable Error for the above confidence interval?
4. If the level of confidence changes to 99%, and all other variables remain unchanged, what will happen to the confidence interval?
5. If the number of graduates returning the survey changes from 300 to 700, all other variables remaining unchanged, what will be effected?

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let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

answer:

idk

step-by-step explanation: