Find an equation of the line that bisects the acute angle formed by the graphs of negative 5X plus 7Y +4 equals zero and 7X minus 5Y +6 equals zero

Sorry to say no very sorry. I feel bad for you sorry.

Step-by-step explanation:

Step-by-step explanation:

x+ y = 0  

and

-2x + 5y + 2 = 0

Step-by-step explanation:

given line

3x+5y+2=0

5x+3y-2=0

solution

when two line bisect each other then line equation of bisector is express as

  1

and here

A1 = 3

B1  = 5

C1 = 2

and

A2 = 5

B2  = 3

C2 = -2

so now put value in equation 1 we get

solve it we get

-2x + 5y + 2 = 0   1

and

3x+5y+2 = - ( 5x+3y-2 )

solve it we get

8x + 8y = 0

x + y = 0  2

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8