HCF and LCM of (1-x^2)(1-y^2)+4xy,1-2xy+y-x^2y+x^2 ​

x2(y2 - 1) Now by using the identity a2 - b2. x2(y2 - 12) = x2(y + 1) (y - 1) Also, factorizing xy2 - 2xy - 3x by taking the common factor 'x' we get, x(y2 - 2y -

Step-by-step explanation:

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

is it 35

step-by-step explanation: