The following set of data represents the age in years of newly married ladies in Desai. 15,25,17,20,22,24,19,16./ This data was collected after Deborah made an allegation that ladies in Desai get married at an age other than 18 years as is required by law. Does this data provide enough evidence at 5% level of significance to believe that the mean ages of ladies getting married in Desai is actually different from 18 years as claimed by Deborah?​

There is no significant evidence to conclude that the mean ages of ladies getting married in Desai is different from 18.

Step-by-step explanation:

Given the data:

15,25,17,20,22,24,19,16

Using calculator :

Mean value, xbar = 19.75

Standard deviation, s = 3.69

Samoke size, n

H0 : μ = 18

H1 : μ > 18

The test statistic :

Tstatistic = (xbar - μ) ÷ (s / sqrt(n))

Test statistic = (19.75 - 18) ÷ 3.69/ sqrt(8))

Test statistic = 1.75 ÷ 1.3046

Test statistic = 1.34

The Pvalue from test statistic ; df = n - 1 = 8 - 1 = 7

Pvalue = 0.111054

Decision :

If Pvalue < α ; reject H0

0.111053 > 0.05 ` Hence, we fail to reject H0

We can conclude that, There is no significant evidence to conclude that the mean ages of ladies getting married in Desai is different from 18.

go hook jvc hgv cj xk jvc 6756

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer