Please help. In one Cartesian plane, sketch the graph of a function that will satisfy the properties below. (Each satisfied property is worth two points. Maximum: 20 pts.)
The function's domain is (−4,4).
The function f is continuous at these intervals: (−4,−2), (−2,2), and (2,4).
The function is discontinuous at x=−2.
The function is discontinuous at x=2.
f(−2)=0
f(2)=0
limx→−4+f(x)=∞
limx→−2−f(x)=0
limx→2+f(x)=0
limx→4−f(x)=−∞

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

191 students play sports and ninety-seven 10th graders were surveyed.

step-by-step explanation: