Find an equation for the perpendicular bisector of the line segment whose endpoints
(8,-6) and (-2,4).
are
answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4
step-by-step explanation:
polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!
complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.
the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7
verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.
a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.
you 're wlecome! : )
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include a picture of the drawing in order for me to
step-by-step explanation:
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