According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal
places, for example: 0.123]
Compute the probability that a randomly selected peanut M&M is not brown.
Compute the probability that a randomly selected peanut M&M is brown or orange.
Compute the probability that three randomly selected peanut M&M's are all yellow.
If you randomly select six peanut M&M's, compute that probability that none of them are brown.
If you randomly select six peanut M&M's, compute that probability that at least one of them is brown.

Answer(In bold)/Step-by-step explanation:

Compute the probability that a randomly selected peanut M&M is not blue

P (blue) = 23%

P (blue)C = 1 - P(blue) = 100% - 23% = 77%

Compute the probability that a randomly selected peanut M&M is green or red.

P (green) = 15%

P (red) = 12%

P (green or red) = P(green) + P(red) = 27%

Compute the probability that three randomly selected peanut M&M’s are all yellow.

P (yellow) = 15%

(P(yellow))3 = 0.338%

There was replacement in the selection process.  

If you randomly select six peanut M&M’s, compute that probability that none of them are brown.

P(brown) = 12%

P(brown)C = 1 - P(brown) = 100% - 12% = 88%

(P(brown)C)6 = 46.440%