The radioactive element plutonium 238 (Pu-238) has a half-life of 88 years. This means that the element loses half of its mass every 88 years. A sample of Pu-238 has a mass of N grams today. How do you determine the amount of the sample remaining after 352 years (4 half-lives)? a. Raise N to the power (1/2)^4.
b. Multiply N by (0.5)^4.
c. Multiply N by 88/352 four times.
d. Raise N to the power of 88/352

Step-by-step explanation:

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3x^3-x^2+6x-9

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!