A) 3.x + y = 11
a)
2x-y=4​

here's the solution,

first equation,

=》3x + y = 11

=》y = 11 - 3x

now, in second equation,

=》2x - y = 4

plugging the value of y as 11 - 3x,

=》2x - (11 - 3x) = 4

=》2x - 11 + 3x = 4

=》5x = 11 + 4

=》x = 15 ÷ 5

=》x = 3

now, plugging the value of x as 3 in equation 1

=》3x + y = 11

=》3 × 3 + y = 11

=》9 + y = 11

=》y = 2

Step-by-step explanation:

3x + y = 11 ...(1)

2x - y = 4 ...(2)

From equation (1) we get,

3x + y = 11

x = 11 - y/3

Now, put the value of x = 11 - y/3 in equation (2) we get,

2x - y = 4

2(11 - y/3) - y = 4

22 - 2y/3 - y = 4

22 - 2y - 3y = 12

22 - 5y = 12

5y = 22- 12

5y = 10

y = 10/5

y = 2

Now, Put the value of y = 2 in equation (1)

3x + y = 11

3x + 2 = 11

3x = 11 - 2

3x = 9

x = 9/3

x = 3

Thus, The value of x is 3 and y is 2

3x + y = 11

3(3) + 2 = 11

9 + 2 = 11

11 = 11

2x - y = 4

2(3) - 2 = 4

6 - 2 = 4

4 = 4

Hence, L.H.S = R.H.S

-TheUnknownScientist

the square root of what number? if you add that, then someone will probably answer the question.