Find the area of a regular octagon with a side length of 5 cm. Round to the nearest tenth

120.7 cm²

Step-by-step explanation:

2( 1 + √2 ) a² = 2( 1+ √2 ) · 5² ≈ 120.7

the eight graders whould be the answer

step-by-step explanation: could you give me 5 stars

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)