Mathematics
Mathematics, 11.04.2021 02:20, jackfrost5

Given X ~ N (300, 15), find P(280 < X < 340). A. 0.2000
B. 0.7460
C. 0.9050
D. 0.9999
E. None of the above

Given X ~ N(300, 15), find the 70th percentile.

A. 0.5244
B. 210.00
C. 307.87
D. 324.96
E. None of the above

Given X ~ N(300, 15), what can be said of the median?
A. The median = mode and the median = the mean.
B. It is the same as the mode.
C. It is less than the average.
D. It is the same as the average.
E. None of the above

Given X ~ N(300, 15) and Z ~ N(0,1), the area to the right of x = 330...
A. is the same as the area to the right of z = 2.
B. P(X > 330) is the same as the area to the right of z = 2 AND to the left of x = 270.
C. is the same as the area to the left of x = 270.
D. is the same as the area to the left of x = 330.
E. None of the above

Given X ~ N(300, 15), find the Interquartile Range (IQR).
A. 0.50
B. 310.12
C. 20.23
D. 289.99
E. None of the above

Given X ~ N(300, 15), find the z-score associated with x = 290.
A. 15/10
B. -10
C. 10/15
D. -10/15
E. None of the above

For what do we use z-scores?
A. Because of the use of technology, there is no longer any use for z-scores.
B. to standardize scores from two or more different normal distributions so that we may compare the scores.
C. to help us calculate uniform and exponential probabilities.
D. to make our calculations easier because the mean = 0.
E. None of the above

Given that X ~ N(10, 2) and Y follows the Exponential Distribution with a mean of 10, which of the following are correct?
A. The median for Y is greater than the median for X.
B. The median for Y is less than the median for X.
C. The percentiles for X and Y are also equal.
D. The median for X and Y are also equal.
E. None of the above

For data that is normally distributed, is it possible for the standard deviation to be larger than the mean?
A. No.
B. Yes.
C. There is not enough information to determine.

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Answers: 3

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Do you know the correct answer?
Given X ~ N (300, 15), find P(280 < X < 340). A. 0.2000
B. 0.7460
C. 0.9050
...

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