If 5x + y = 20 and 10x - 2y = 50 are two linear equations in two variables. Find the value of x and y. x = 1, y = 1
x = 2, y = 1/2
x = 9/2, y = -5/2
x = 1, y = 5/2

x = 9/2, y = -5/2

Step-by-step explanation:

5x + y = 20

10x - 2y = 50

There's multiple ways to do this, but I will solve using substitution.

Isolate variable y on the first equation.

5x + y = 20

y = 20 - 5x

Substitute the value of y for 20 - 5x in the second equation.

10x - 2(20 - 5x) = 50

Use distributive property:

10x - 40 + 10x = 50

Combine like terms:

20x - 40 = 50

20x = 90

x = 90/20

x = 9/2

Substitute x for 9/2 and solve for y:

y = 20 - 5(9/2)

y = 20 - 45/2

y = 40/2 - 45/2

y = -5/2

x =9/2, y = -5/2

Step-by-step explanation:

5(9/2) + -(5/2)= 20

45/2 + -5/2 = 20

40/2 = 20

10(9/2) - 2(-5/2) = 50

90/2 + 10/2 = 50

45 + 5 = 50

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.