What is the volume of a sphere with a surface area of 16pi ft^2?

B

Step-by-step explanation:

Sphere Surface Area = 4 • π • r²

For it to equal 16 PI, then radius must equal 2

4*PI*2*2 = 16 PI

Sphere Volume = 4/3 • π • r³

Sphere Volume = 4/3 • π • 2^3

Sphere Volume = 4/3 *PI * 8

Sphere Volume = 32 / 3 PI

Sphere Volume = 10.666 PI cubic feet AND I think that is answer B

which SHOULD read 10 (2/3) PI ft^3

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)