Find the equation of a line that is perpendicular to 4x+6y=1 and that has a greater intercept to the line 2x+3y=18

The equation of the the line that is perpendicular to 4·x + 6·y = 1 and that has a greater intercept to the line 2·x + 3·y = 18 can be 2·y - 3·x = 14

Step-by-step explanation:

The line which is perpendicular to the required line = 4·x + 6·y = 1

The line with which the required line has a greater intercept = 2·x + 3·y = 18

Solution;

The relationship between the slope, m₁, of a straight line, y = m₁·x + c₁ perpendicular to another straight line, y = m₂·x + c₂, with slope m₂ is given as follows;

m₁ = -1/m₂

Rewriting the equation of the given line in slope and intercept form gives;

4·x + 6·y = 1

6·y = 1 - 4·x

y = 1/6 - 4·x/6 = 1/6 - 2·x/3 =  1/6 - (2/3)·x

∴ y = 1/6 - (2/3)·x

Therefore, the slope, 'm₁', of the line y = 1/6 - (2/3)·x, is m₁ = -(2/3)

The slope of the perpendicular line, is therefore, m₁ = -1/m₂

∴ m₂ = -1/m₁

m₂ = -1/(-(2/3)) = 3/2

The intercept of a straight line of the form y = m·x + c is 'c'

The intercept of the line 2·x + 3·y = 18 is obtained by rewriting the equation of the line in slope and intercept form as follows;

2·x + 3·y = 18

y = 18/3 - (2/3)·x = 6 - (2/3)·x

y = 6 - (2/3)·x = -(2/3)·x + 6

y = -(2/3)·x + 6

By comparing the above equation to the equation, y = m·x + c, we have;

c = 6

The intercept of the line y = -(2/3)·x + 6, which is the same line as 2·x + 3·y = 18 is 6

∴ The intercept of the required line, c₂ > 6

The equation of the required  line in slope and intercept form, y = m·x + c, can therefore be;

y = (3/2)·x + 7

By multiplying by 2, we get;

2·y = 3·x + 14

∴ The equation of the line can be 2·y - 3·x = 14.

found it xd it ok yt

i think the correct option is the second option.