What are the domain, range, and asymptote of h(x) = (0.5)x – 9? domain: {x | x > 9}; range: {y | y is a real number}; asymptote: y = 9
domain: {x | x > –9}; range: {y | y is a real number}; asymptote: y = –9
domain: {x | x is a real number}; range: {y | y > 9}; asymptote: y = 9
domain: {x | x is a real number}; range: {y | y > –9}; asymptote: y = –9

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.

hi

step-by-step explanation: