Mathematics, 09.04.2021 19:00, maliyahclays

Can yu write a linear equation for this

Answers: 2

Show answers

Other questions on the subject: Mathematics

Mathematics, 21.06.2019 16:30, angeline310

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Answers: 2

continue

Mathematics, 21.06.2019 18:20, julieariscar769

Inez has a phone card. the graph shows the number of minutes that remain on her phone card a certain number of days.

Answers: 2

continue

Mathematics, 21.06.2019 20:00, Clervoyantyvonne

Simplify (2^5/3^2)^4 a. 2^20/3^8 b. 2^9/3^8 c. 8^5/12^2 d. 2/3^2

Answers: 1

continue

Mathematics, 21.06.2019 20:30, nosugh

If m∠abc = 70°, what is m∠abd? justify your reasoning. using the addition property of equality, 40 + 70 = 110, so m∠abd = 110°. using the subtraction property of equality, 70 − 30 = 40, so m∠abd = 30°. using the angle addition postulate, 40 + m∠abd = 70. so, m∠abd = 30° using the subtraction property of equality. using the angle addition postulate, 40 + 70 = m∠abd. so, m∠abd = 110° using the addition property of equality.

Answers: 2

continue

Do you know the correct answer?

Can yu write a linear equation for this
...