A sheet of paper has a perimeter of 39 inches. If the width of the paper is 8.5 inches, what is the length of the sheet of paper?

length of the sheet of paper is 11 in.

Step-by-step explanation:

Let "a" = short end of paper and let "b" = long end of paper.

Let "p" = perimeter

1st equation:   p = 39"

2nd equation:  2a + 2b = p   plug in "39" for diameter;  result:

2nd equation:  2a + 2b = 39

3rd equation:  b = 2a - 6

replace "b" in 2nd equation with "2a - 6" from 3rd equation, result:

2a + 2(2a - 6) = 39  simplified to:

2a + 4a - 12 = 39    simplified to:

6a - 12 = 39            simplified to:

6a = 51                   simplified to:

a = 51/6  =  8.5

so, a =  short end of paper = 8.5 inches

In 3rd equation (b = 2a - 6), substitute "a" with "8.5"

3rd equation becomes:   b = 2(8.5) - 6    simplified to:

b = 17 - 6  =  11

so, b = long end of paper = 11 inches

answer to question is:  dimensions of paper are ---

8.5 inches wide by 11 inches long

The answer is 11

Step-by-step explanation:

So perimeter is base+ base+length+length. Therefore you take 8.5+8.5 which is 17 and subtract it from 39 to get 22. You take 22 and divide it by 2 which leaves you with 11.

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.