Mathematics, 30.08.2019 02:30, sam9043

How many grams of o2 are needed in a reaction that produces 75 g of na2o?

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Suppose you're talking about the following reaction: 4 Na + O2 ---> 2 Na2O If this is not the reaction then just keep reading, you'll find out how to calculate it your self! This is an pretty easy question because it involves a simple trick. With this reaction you're goal is to have 75 gram's Na2O. If the reaction, the molar weight's, one amount in grams of one product or reactant beside oxygen, and the stoichometry is know we can calculate the grams of oxygen. The molar weight of Na2O is 61,97893856 g/mol O2 is 31,9988 g/mol we have 75 gram Na2O divided by 61,97793856 it brings us 1,21 mol. Because the S.U unit mole is a variabel for the amount of molecules we can see that, because 2 Na2O molecules form from 1 molecule O2 and four molecules Na, that dividing 1,21 by 2 brings us the amount of molecules in mole for O2. Keep in mind that the mole is just a value that stands for an amount of molecules This is because an amount of molecules in one mole weigh 31,9988 gram. That is the molair weight!!! So for our final conclusion I present to you THE ANSWER :) (1,21/ 2) * 32 = around 19,4 grams!

answered: AshlynPlayz45

50 grams of O2 is needed because for every one part of Na, two parts of O2 are needed. You can just take 75 and divide it by three then multiply by 2

answered: Guest

binomial distribution

median= 2

range = 7-0 = 7

how to find median?

no. of term=28

median=(28+1)/2=14.5th term

the 14th and 15th term are 2, therefore the median is (2+2)/2 = 2

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answered: Guest

the range of a function is the range of y-values for which it is defined, or exists. given that we are only looking at the y-values, we can already discount the first two answers as they deal with the domain of the function (range of x-values).

now, what we need to do is find the smallest and highest y-values for which the function is defined. if you'd like, you could take a ruler and start at the very bottom of the graph, find the lowest point, then move the ruler higher and higher until you reach the highest point. doing so either in your head or with an actual ruler, we can see that the lowest y-value is -5 and the highest y-value is -1.

the question now remains as to whether they are included in the range (fourth answer) or excluded (third answer). the key here is to recognise whether they are marked with an open or a closed circle. since both (-2, -5) and (2, -1) are marked with a closed circle, they are points that exist on the graph and are thus included in the range (note that if they were marked with an open circle like (4, -2) then that would signify that there is a break in the graph at that point).

thus, the fourth answer, (y | -5 ≤ y ≤ -1), is correct.

also note that usually it is good practice to scan your eye inbetween the highest and lowest point for any breaks in the graph - we do have one here at (4, -2), however -2 is still included in the range because there is another point that is included in the graph with the same y-value, ie. point (1, -2).

i hope that but if you require any further explanation don't hesitate to comment below.