Suppose that f(x)=f(g(x)) and g(14)=2, g'(14)=5, f'(14)=15, and f'(2)=12. find f'(14.)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.