The x-axis contains the base of an equilateral triangle rst. the origin is at s. vertex t has coordinates (2h, 0) and the y-coordinate of r is g, with g > 0.

enter the coordinates for the midpoint of st:

enter the x- coordinate of r:

Coordinates of Mid Point of ST is ( h , 0 ) and x-coordinate of R is   .

Step-by-step explanation:

Given: Coordinate of S ( 0 , 0 )  ,  Coordinate of T ( 2h , 0 )

           y-coordinate of R = g

Coordinates of Mid point of ST =

                                                    = ( h , 0 )

let x-coordinate of point R be x

Distance of RS = Distance of ST

Squaring both sides, we get

So, x-coordinate of R is

Therefore, Coordinates of Mid Point of ST is ( h , 0 ) and x-coordinate of R is   .

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!