Mathematics, 09.04.2021 02:00, natalie2sheffield
P(x)=(256-x^2/256)^1/2 for 0≤X≤65536
The market for Keppelbells is governed by the quantity x sold in millions per week and the selling price p in dollars according to the above function p(x). We wish to find the quantity that will maximize revenue, what selling price this corresponds to and the resulting maximized revenue. In canvas you must show the formula for revenue R(x), how to compute R'(x), and how to solve R'(x)=0.
1. What is the revenue function R(x)=
2. What is the derivative of the revenue function R'(x)=
3. What is the revenue when x=0?
4. What is the revenue when x=65536?
5. For what value of x to the nearest 0.01 million Keppelbells is R'(x)=0?
6. What is the selling price corresponding to the above quantity? Specify to the nearest cent.
7. What is the maximum revenue? Specify to the nearest 0.1 million dollars,
Answers: 3
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Prove that the value of the expression 7^8–7^7+7^6 is divisible by 43.
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In a test for esp (extrasensory perception), a subject is told that cards only the experimenter can see contain either a star, a circle, a wave, or a square. as the experimenter looks at each of 20 cards in turn, the subject names the shape on the card. a subject who is just guessing has probability 0.25 of guessing correctly on each card. a. the count of correct guesses in 20 cards has a binomial distribution. what are n and p? b. what is the mean number of correct guesses in 20 cards for subjects who are just guessing? c. what is the probability of exactly 5 correct guesses in 20 cards if a subject is just guessing?
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P(x)=(256-x^2/256)^1/2 for 0≤X≤65536
The market for Keppelbells is governed by the quantity x sold...
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