A circular pool has a footpath around the circumference. The equation x2 + y2 = 2,500, with units in feet, models the outside edge of the pool. The equation x2 + y2 = 3,422.25, with units in feet, models the outside edge of the footpath. What is the width of the footpath? A. 8.5 ft
B. 17 ft
C. 30 ft
D. 58.5 ft

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

111

step-by-step explanation:

hi! i think the answer is 1/2 : )

pls refer ro the top for answer