The Taylor series for f(x)=100+x−−−−−−√f(x)=100+x at a=0a=0 is ∑n=0[infinity]cn(x)n.∑n=0[infinity] cn(x)n. Find the first few coefficients. c0=c0= 10 c1=c1= 1 20​ c2=c2= [−( 1 4​)( 1 100 3 2​​)] 2​ c3=c3= [( 3 8​)100(− 5 2​)] 6​ Find the error in approximating 101−−−√=f(1)101=f(1) using the third degree Taylor polynomial of ff at a=0.a=0. That is, find the error of the approximation 101−−−√≈T3(1)101≈T3(1). The absolute value of the error is

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%

Lil