(PLEASE ANSWER WILL GIVE BRAINLIEST PLEASE!) The equation for the motion of an object with constant acceleration is d=vt+0.5at2
where d is distance traveled in ft, v is starting velocity in ft/s, a is acceleration in
ft/s2, and t is time in seconds. A racecar begins with a velocity of 200 ft/s and
accelerates at 100 ft/s2.
Write an expression for the distance the car travels after t seconds.

step-by-step explanation:

goog be able to you with that maybe

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

a

step-by-step explanation: