Cs. The width of a rectangle is
12 cm less than the length.
The area is 64 cm2. Find the
length and width.

Length of rectangle = 16 cm

Width of rectangle = 4 cm

Step-by-step explanation:

Given:

Area of rectangle = 64 cm²

Find:

Length and width

Computation:

Assume;

Length of rectangle = a

So,

Width of rectangle = a -12

Area of rectangle = l x b

So,

a(a-12) = 64

a² - 12a - 64 = 0

a² - (16-4)a - 64 = 0

a² - 16a+ 4a - 64 = 0

a (a-16) + 4(a-16)= 0

(a-16)(a+4) = 0

a= 16 , a = -4

So,

Length of rectangle = 16 cm

Width of rectangle = a -12

Width of rectangle = 16 -12

Width of rectangle = 4 cm

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)