There are twice as many girls as boys in Mr. Terpathi’s 7th grade math class. Each of the girls gave him an oatmeal cookie, and each of the boys gave him a chocolate cookie. Mr Terpathi arranged the cookies in one row with a chocolate cookie farthest to the right. Which of the following must be true? A. The cookie farthest to the left is chocolate.

B. The cookie farthest to the left is oatmeal.

C. There are at least two chocolate cookies next to each other.

D. There are at least two oatmeal cookies next to each other.

E. Mr. Terpathi received more chocolate cookies than oatmeal cookies.

D. There are at least two oatmeal cookies next to each other.

Step-by-step explanation:

Alright so basically we can use process of elimination to determine what is true or false so

A. States the farthest to the left is chocolate but we can't prove that because all we know is the cookie farthest to the right is chocolate so this is false

B. Same reason as A we cannot prove what cookie is farthest to the left because we are not given a pattern so B is false

C. Since there are definitely twice as many girls as boys in the class and that also means there are twice as many oatmeal cookies then we cannot prove that 2 chocolate cookies have to be next to each other so also false

D. This has to be true because if there are twice as many girls as boys and more oatmeal than chocolate then is whatever cookie line combinataion we will have at least 2 oatmeal cookies next to each other So this is true

E. This is most definitely not true because the question tells us that twice as many girls gave him oatmeal so if anything there are more oatmeal cookies

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

do i do it on a graph?

step-by-step explanation: