A coach throws a football from a height of 4 feet with an initial velocity of 59 feet per second at an elevation angle of 45°. Which parametric equations represent the path of the football? x(t) = 59sin(45o)t and y(t) = –16t2 + 59cos(45o)t x(t) = 59cos(45o)t and y(t) = –16t2 + 59sin(45o)t x(t) = 59cos(45o)t and y(t) = –16t2 + 59sin(45o)t + 4 x(t) = 59sin(45o)t and y(t) = –16t2 + 59cos(45o)t + 4

the 3rd option is right

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24