A chocolate shop sells chocolates with a variety of different fillings. hazelnut 68
caramel 8
orange 8

What is the probability that a randomly selected chocolate will have caramel filling?

Write your answer as a fraction or whole number.

There is a chance of picking caramel-filled chocolate.

Step-by-step explanation:

To set this up, you need to make it a fraction. The denominator of the fraction is how many total chocolates you can pick from. You can figure this out by adding all of the chocolate choices together:

68 hazelnut + 8 caramel + 8 orange = 84 chocolates.

The numerator is defined by the number of caramel chocolates, in this case it is 8. That means the fraction will look like:

Now that can be simplified down. I divided the top and bottom both by 4 to get   and that is as far down as it can go. Therefore that is the probability you will get a caramel-filled chocolate.

i think that you should ask google for the answer to that problem because if we don't know it google does

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!