Solve the system and explain what the results mean according to your scenario.

2x + y = 9
3x + 4y = 26

Y=9-2x
3x+4y=26

3x+4(9-2x)=26
3x+36-8x=26
-5x=-10
x=10/5
x=2
2(2)+y=9
y=5                                                           x=2  <
                                                                 y=5  <

2(2)+5=9
4+5=9

3(2)+4(5)=26
6+20=26

The solution to the problem is as follows:

By elimination method:

2x + y = 9 (1)
3x + 4y = 26 (2)

Multiply eq (1) by -4:

-8x -4y = -36
(+)   3x + 4y = 26

4y will be cancelled out:

5x = -10

x = -2

Substitute x = -2 on eq (1):

2(-2) + y = 9

y = 9 + 8 = 17

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You just divide and you will find x