20 POINTS! Using the equation (x^2 − 1)^3, and the interval [−1, 2], find the absolute minimum

-1

Step-by-step explanation:

f(x) = (x² - 1)³

the minimum will occur when the derivative equals zero

f'(x) = 6x(x² - 1)²

0 = 6x(x² - 1)²

if we expand this, we end up with a fifth level polynomial which is VERY difficult to resolve. Let's just take a simple route and know that the 6x = 0 when x = 0 and therefore the whole equation will = 0

x = 0

f(0) = (0² - 1)³ = -1³ = -1

Here's a plot of the equation f(x) = (x² - 1)³ to verify our result.

We see that -1 is the minimum in the range -1 ≤ x ≤ 2

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.

step-by-step explanation:

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