Find the third, fifth and tenth term sequence described by each rule
a(n)=4+(n-)

a(n)=-2(n-)

In order to solve for a nth term in an arithmetic sequence, we use the formula written as:

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

THIRD
A3=4+(3-1)(-5)
A3 = -6

A(3)=-2(3-1)(-5)
A3 = 20
 
FIFTH
A5=4+(5-1)(-5)
A5 = -16

A(5)=-2(5-1)(-5)
A5 = 40

TENTH
A10=4+(10-1)(-5)
A10 = -41

A(10)=-2(10-1)(-5)
A10 = 90

Main idea on left, details on right