Two square posters are hanging on a wall. The large poster has an area of 144 square units, and the small poster has an area of 100 square units. How much bigger is the perimeter of the large poster than the perimeter of the small poster?

8

Step-by-step explanation:

If you do the math with the area to find out the perimeter, and you will find the largest one to be the poster with the area of 144 , and the smaller one to be the one with the area of 100

Length= squre root of area

Length of big poster = squre root of 144

=12

Length of small poster=squre root of 100

=10

The perimeter = 4*length

Big poster perimeter=4*12=48

Small poster perimeter =4*10=40

The difference= 48 - 40 = 8

It is bigger by 8

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen