Mrs. Haba's hourly wage change by a constant percent? Mrs. Haba's hourly wage is $20 per hour in the first year, $22 per hour the second year, $24.20 per hour the third year, and
so on.
O Mrs. Haba's starting hourly wage is $30.00 per hour the first year, and it increases by $2.50 each year.
O Mrs. Haba's starting hourly wage is $28.00 per hour. She receives a $0.75 per hour raise after one year, a $1.00 per hour
raise after the second year, a $1.25 raise after the third year, and so on.
O Mrs. Haba's starting hourly wage is $15.00 per hour. Her hourly wage is $15.75 after one year, $17.00 after two years,
$18.75 after three years, and so on

i'm sure goog can you get that answer

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

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