In fig if AB II CD , CD II EF and y : z = 3 : 7 , find x.

In the given figure,AB∥CD,CD\parallel EFandy:z=3:7$$

Let y=3a and z=7a

∠DHI=y(vertically opposite angles)

∠DHI+∠FIH=180 ∘

 (Interior angles on the same side of the transversal)

⇒y+z=180 ∘

⇒3a+7a=180 ∘

⇒10a=180 ∘

 or a=18 ∘

∴y=3×18 ∘

=54  ∘

 and z=7×18  ∘

=126  ∘

Also,x+y=180 ∘

⇒x+54 ∘

=180 ∘

∴x=180 ∘

−54 ∘

=126 ∘

Hence,x=126 ∘

Step-by-step explanation:

i think the length is 12 and the width is 17