Find the trigonometric ratios as simplified fractions and as decimals to the nearest thousandths (3 decimal places) 16 34
HElp me pls ;-;

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

Select the quadratic that has root x = 8 and x = -5

If f(x) = x+8 and g(x) = 4x- 3, find (f+g)(x)