A train arrives at a station and waits 3.5 minutes before departing. Another train arrives at the station 16 minutes later, repeating the cycle. Identify the probability that a train will not be at the station when you arrive.

Step-by-step explanation:

so we can safely say that one train will be there for 3.5 minutes and it will be gone for 16 minutes before another train comes and repeats the cycle.

we want how many minutes that the train will not be there over the total time that is possible so that would be

16/(16+3.5)

16/19.5

32/39

Hope that helps :)

Solution given;

total time =3.5+16=19.5min

time of arriving of train's =16 min later

now

probability that a train will not be at the station when you arrive.=16/19.5=32/39 is your answer

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p