PLEASE HELP The box plot below shows the total amount of time, in minutes, the students of a class surf the Internet every day:
Daily Internet Surfing
40
60
H
20
35
80
95
50 65
Time (minutes)
Part A: List two pieces of information that are provided by the graph and one piece
of information that is not provided by the graph. (4 points)
Part B: Calculate the interquartile range of the data, and explain in a sentence or two
what it represents. (4 points)
Part C: Explain what affect, if any, there will be if an outlier is present. (2 points)

$649.60

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

i’m kinda new to precal but your answer should be 21. hope i got it right.

step-by-step explanation: