Write the equation of the line parallel to the y axis at a distance of 7 units form it to is left​

x = -7

Step-by-step explanation:

Two parallel lines are lines that never intersect each other.

The y-axis can be written as x = 0.

Then if we want a parallel line to this one, it must be something like x = b

such that b ≠ 0.

Now we want that the distance between our line and the line x = 0 is 7 units to the left

(remember that the left is the negatie side of the axis)

then we can write:

b - 0 = -7

b = -7

The parallel line is x = -7

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

my answer got deleted but it's a

step-by-step explanation: