What is a linear function in the form y=mx+b for the line passing through (2, -4) with y-intercept 2?

A linear function in the form y = m·x + b for the line passing through the point (2, -4) with y-intercept 2 is;

y = -3·x + 2

Step-by-step explanation:

From the question, it is required to find the a linear equation passing through the point (2, - 4) with a y-intercept 2 in the form y = m·x + c

Given that the y-intercept is the point at which the line cuts the y-axis, we have, x = 0

Therefore, we have the point on the line representing the y-intercept is (0, 2)

Therefore, the slope of the graph is given as follows;

Therefore, we have;

The equation of the graph in point and slope is given as follows;

y - 2 = -3 × (x - 0) = -3 × x

Therefore, the equation of the line in the form y = m·x + c is given as follows;

y - 2 + 2 = -3 × x + 2

∴ y = -3·x + 2

The equation of the line in the form y = m·x + c is y = -3·x + 2.

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

b

step-by-step explanation: